t^2-9t-8=0

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Solution for t^2-9t-8=0 equation: 



t^2-9t-8=0

a = 1; b = -9; c = -8;
Δ = b2-4ac
Δ = -92-4·1·(-8)
Δ = 113
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{113}}{2*1}=\frac{9-\sqrt{113}}{2}
$


$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{113}}{2*1}=\frac{9+\sqrt{113}}{2}
$

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